А) S — 3) C l 2 Cl_{2} C l 2 , H g Hg H g , H 2 H_{2} H 2
S + C l 2 = S C l 2 S + Cl_{2} = SCl_{2} S + C l 2 = S C l 2
H g + S = H g S Hg + S = HgS H g + S = H g S
H 2 + S → t H 2 S H_{2} + S \overset{t}{\rightarrow} H_{2}S H 2 + S → t H 2 S
Не подходят: S + H 2 O = S + H_{2}O \cancel{=} S + H 2 O = , S + B a O = S + BaO \cancel{=} S + B a O = , S + H C l = S + HCl \cancel{=} S + H C l =
Б) Ba — 2) B r 2 Br_{2} B r 2 , H 2 O H_{2}O H 2 O , H F HF H F
B a + B r 2 = B a B r 2 Ba + Br_{2} = BaBr_{2} B a + B r 2 = B a B r 2
B a + 2 H 2 O = B a ( O H ) 2 + H 2 ↑ Ba + 2H_{2}O = Ba(OH)_{2} + H_{2}\uparrow B a + 2 H 2 O = B a ( O H ) 2 + H 2 ↑
B a + 2 H F = B a F 2 + H 2 ↑ Ba + 2HF = BaF_{2} + H_{2}\uparrow B a + 2 H F = B a F 2 + H 2 ↑
Не подходят: B a + C O = Ba + CO \cancel{=} B a + C O = , B a + N a 2 O = Ba + Na_{2}O \cancel{=} B a + N a 2 O =
В) F e 2 O 3 Fe_{2}O_{3} F e 2 O 3 — 4) H C l HCl H C l , A l Al A l , C O CO C O
F e 2 O 3 + 6 H C l = 2 F e C l 3 + 3 H 2 O Fe_{2}O_{3} + 6HCl = 2FeCl_{3} + 3H_{2}O F e 2 O 3 + 6 H C l = 2 F e C l 3 + 3 H 2 O
F e 2 O 3 + 2 A l → t A l 2 O 3 + 2 F e Fe_{2}O_{3} + 2Al \overset{t}{\rightarrow} Al_{2}O_{3} + 2Fe F e 2 O 3 + 2 A l → t A l 2 O 3 + 2 F e
F e 2 O 3 + 3 C O → t 2 F e + 3 C O 2 Fe_{2}O_{3} + 3CO \overset{t}{\rightarrow} 2Fe + 3CO_{2} F e 2 O 3 + 3 C O → t 2 F e + 3 C O 2
Не подходят: F e 2 O 3 + H 2 O = Fe_{2}O_{3} + H_{2}O \cancel{=} F e 2 O 3 + H 2 O = , F e 2 O 3 + B r 2 = Fe_{2}O_{3} + Br_{2} \cancel{=} F e 2 O 3 + B r 2 =
Г) S O 2 SO_{2} S O 2 — 5) H 2 O H_{2}O H 2 O , N a 2 O Na_{2}O N a 2 O , H 2 O 2 H_{2}O_{2} H 2 O 2
S O 2 + H 2 O = H 2 S O 3 SO_{2} + H_{2}O = H_{2}SO_{3} S O 2 + H 2 O = H 2 S O 3
S O 2 + N a 2 O = N a 2 S O 3 SO_{2} + Na_{2}O = Na_{2}SO_{3} S O 2 + N a 2 O = N a 2 S O 3
S O 2 + H 2 O 2 = H 2 S O 4 SO_{2} + H_{2}O_{2} = H_{2}SO_{4} S O 2 + H 2 O 2 = H 2 S O 4
Не подходят: S O 2 + H F = SO_{2} + HF \cancel{=} S O 2 + H F = , S O 2 + P 2 O 5 = SO_{2} + P_{2}O_{5} \cancel{=} S O 2 + P 2 O 5 = , S O 2 + H g = SO_{2} + Hg \cancel{=} S O 2 + H g =
Ответ: 3245