Задание 7 ЕГЭ по химии

1235

А) $H_{2}O$ — 1)

• $P_{2}O_{5} + 3H_{2}O = 2H_{3}PO_{4}$

• $2Na + 2H_{2}O = 2NaOH + H_{2}\uparrow$

• $Al_{2}S_{3} + 6H_{2}O = 2Al(OH)_{3}\downarrow + 3H_{2}S\uparrow$

Б) $O_{2}$ — 2)

• $2H_{2}S + 3O_{2} \overset{t}{\rightarrow} 2SO_{2} + 2H_{2}O$

• $4FeO + O_{2} \overset{t}{\rightarrow} 2Fe_{2}O_{3}$

• $4NH_{3} + 3O_{2} \overset{t}{\rightarrow} 2N_{2} + 6H_{2}O$

В) $Si$ — 3)

• $Si + 2Cl_{2} \overset{t}{\rightarrow} SiCl_{4}$

• $Si + 2KOH + H_{2}O = K_{2}SiO_{3} + 2H_{2}\uparrow$

• $2Ca + Si \overset{t}{\rightarrow} Ca_{2}Si$

Г) $CuSO_{4}$ — 5)

• $CuSO_{4} + H_{2}S = CuS\downarrow + H_{2}SO_{4}$

• $CuSO_{4} + 2NaOH = Cu(OH)_{2}\downarrow + Na_{2}SO_{4}$

• $2CuSO_{4} + 4KI = 2CuI\downarrow + I_{2}\downarrow + 2K_{2}SO_{4}$

Набор 4 не подходит ни одному веществу: $CH_{4} + H_{2}O \cancel{=}$ (без катализатора и нагревания), $CO_{2} + O_{2} \cancel{=}$, $CH_{4} + Si \cancel{=}$, $CuSO_{4} + CO_{2} \cancel{=}$.

Ответ: 1235